Membrane fusion is believed to proceed via
intermediate structures called stalks. Mathematical analysis of the
stalk provided the elastic energy involved in this structure and
predicted the possible evolution of the overall process, but the
energies predicted by the original model were suspiciously high. This
was due to an erroneous assumption, i.e., that the stalk has a figure
of revolution of a circular arc. Here we abandon this assumption and
calculate the correct shape of the stalk. We find that it can be made
completely stress free and, hence, its energy, instead of being
positive and high can become negative, thus facilitating the fusion
process. Based on our new calculations, the energies of hemifusion, of
complete fusion, and of the pore in a bilayer were analyzed.
Implications for membrane fusion and lipid phase transitions are discussed.
 |
INTRODUCTION |
Membrane fusion plays a fundamental role in
cell physiology. It is even believed to be a key event in the origin of
life (Norris and Raine, 1998
). For this reason it has attracted the
intense interest of numerous researchers who have attempted to develop a model of this process (see Reviews and References therein,
Chernomordik et al., 1995b
; Jahn and Sudhof, 1999
; Zimmerberg and
Chernomordik, 1999
; Burger, 2000
; Stegmann, 2000
; Melikyan et al.,
2000
). Both biological and artificial membrane fusion involves the
merger of two phospholipid bilayers in an aqueous environment. In the early 1980s a qualitative picture of this process emerged suggesting that fusion proceeds via local contact between two lipid bilayers. Hui
et al. (1981)
termed this contact "a point defect" and proposed that it represented an intermediate stage of fusion. It was clear that
membranes could not expose their hydrophobic interiors to water
(reflected by Gingel's famous statement: "membranes hate edges."
And he went on: "All our ideas of membrane transformations are based
on this fact") (Gingell and Ginsberg, 1978
). Therefore, to make a
connection between two membranes, their monolayers must be strongly
bent into an hourglass shape. This structure was called a stalk, and
the whole mechanism was called the stalk model. Its mathematical
analysis was performed in 1983 (Kozlov and Markin, 1983
) with the first
English publication appearing in 1984 (Markin et al., 1984
).
Mathematical implementation of the stalk model was based on
calculation of the elastic energy of the curved monolayers and elucidation of the chain of events leading either to complete fusion or
to abortion of the process. The model proved to be very attractive and
was adopted in numerous studies, both experimental and theoretical
(Leikin et al., 1987
; Kozlov et al., 1989
; Nanavati et al., 1992
;
Siegel, 1993
; Chizmadzhev et al., 1995
, 1999
, 2000
; Siegel, 1999
;
Kuzmin et al., 2001
). Its success was based on its ability to explain a
number of experimental observations (Monck and Fernandez, 1994
;
Chernomordik et al., 1995a
,b
, 1997
; Chernomordik, 1996
; Melikyan et
al., 1997
; Basanez et al., 1998
; Lee and Lentz, 1998
; Zimmerberg and
Chernomordik, 1999
; Goni and Alonso, 2000
; Razinkov and Cohen, 2000
).
Later on the model was further developed to include additional features
such as hydrophobic voids (Siegel, 1993
), fusion pore dilatation in
stages (Chizmadzhev et al., 1995
), relative sliding of monolayers
(Chizmadzhev et al., 1999
), role of membrane tension (Nanavati et al.,
1992
; Chizmadzhev et al., 2000
), et cetera.
However, all these papers had to deal with one significant
difficulty: because of the high curvature of the stalk, the calculation of its elastic energy inevitably resulted in very high values, up to
hundreds kT. D. Siegel wrote in 1999, "It is troubling that energies predicted for stalk and transmonolayer contact (TMC) intermediates are so high." This energy is too high and raises doubts
on the feasibility of the whole model. From the very beginning (1983, 1984) significant efforts were spent in finding a way for the stalk to
decrease its energy. The obvious factor to consider was the spontaneous
curvature of lipid monolayers. This helped to some extent but at the
expense of a necessitating assumption of very high spontaneous
curvature at the limit of reasonable values. This struggle with the
high bending energy of the stalk continues to this day, sometimes
eliciting very ingenious ideas and suggestive terminology (Kuzmin et
al., 2001
).
This stalk paradox is rather disturbing: the model seems to be
intuitively reasonable and agrees with experimental observations, but
it suffers from inherent difficulty. We believe that the resolution of
this paradox should be found within the stalk model proper rather than
by enlisting additional and sometimes artificial considerations. To
this end we performed an analysis of the stalk model ab initio. We
found that with the correct mathematical treatment of the model all of
the difficulties researchers had been struggling with disappeared. Indeed, these difficulties were simply the result of a single unjustified assumption in the stalk model.
The source of these apparent difficulties is the shape of the stalk.
Since the original papers (Kozlov and Markin, 1983
) the shape of the
stalk was not calculated but rather postulated to be the figure of
revolution of a circular arc. It was this postulate that brought about
a very high bending energy of the stalk. So, following Zimmerberg
(2000)
, we asked the same question: "Are the curves in all the right
places?" As we now report, with the right shape of this intermediate
structure the stalk can be made completely stress free and its bending
energy reduced to zero or even to negative values.
Thus, the numerical results of the original paper (Kozlov and Markin,
1983
) are not valid for the properly shaped stalk. Unfortunately, all
subsequent theoretical papers devoted to the stalk model followed the
lead without questioning the postulate of circular shape. Therefore
their conclusions regarding the high bending energy are also wrong. One
of us (V.S.M.) is personally responsible for this unjustified
assumption and we feel obligated to correct this inaccuracy in the
stalk analysis.
 |
THEORETICAL |
Original stalk model
In the original model of 1983 (Kozlov and Markin, 1983
) the stalk
was visualized as an hourglass-shaped local connection between two
membranes. It could be comprised of one or two monolayers of opposing
membranes, producing either a monolayer or bilayer stalk. Later the
monolayer stalk was accepted as a key intermediate in the overall
fusion process known as a hemifusion stage, and the bilayer stalk was
baptized a fusion pore. The stalk could form after direct closure upon
one another of two bulging defects in opposing membranes (layers)
having initial curvature, cinit, and a
spontaneous curvature, c0.
It was assumed that the stalk and surrounding membranes form an
axisymmetrical body of revolution (Fig.
1) with the neutral surface (dotted line)
drawn somewhere in the middle of the layer transformed into the stalk.
Here a is the shortest distance from the neutral surface to
the axis of revolution, r is the marginal radius of the
stalk, b is the distance from the axis of revolution to the
point where the branches of the stalk become horizontal. Parameters
a and b could be called the neck and the width of
the stalk. In the original version of the model b = a + r. The coordinates of the contour are x and
z, and the angle between the contour and horizontal line is
.

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FIGURE 1
Steps in membrane fusion. Solid lines represent
hydrophilic surfaces, thin lines represent hydrophobic, dotted lines
represent neutral surfaces. (A) Parameters of the stalk.
(B) Hemifusion, initial stage. (C) Hemifusion,
transmonolayers contact. (D) Complete fusion fusion pore.
|
|
According to Helfrich (1973)
, the density of bending energy accumulated
in the stalk is given as
|
(1)
|
in which
is bending rigidity and cm and
cp are principal curvatures along the meridian
and parallel to the body of revolution representing the stalk. The
energy associated with Gaussian curvature was neglected as it became
customary in all subsequent papers. The energy of the stalk was defined
as its elastic energy minus the initial elastic energy of two layers
without stalks:
|
(2)
|
The integrals are taken over the total surface of the stalk.
The first integral represents the bending energy of the stalk membrane
and the second integral is equal to the bending energy of the initial
membrane. The stalk energy Ws was found to be
|
(3)
|
If the fusing membranes initially were planar,
cinit = 0, then
|
(4)
|
In the absence on spontaneous curvature
(c0 = 0), the bending energy depends only
on the ratio r/a; the function has the minimum equal to
Emin = 3.791
, which occurs at
r/a = 1.671. Final results depend on the value of the
bending rigidity. Chizmadzhev et al. (1995)
assumed that bilayer
rigidity equals ~10
19 J, giving the minimum monolayer
stalk energy of Emin = 45.5 kT. If, as more
often assumed,
10 kT, the minimum energy of the stalk is 37 kT.
If spontaneous curvature of the bent layer is not zero, then its
energy depends on the variables r and a
separately. The initial monolayer stalk has a
1 nm. For c0 =
0.01
nm
1 the minimal energy of 3.68,
44.2 kT occurs at r = 1.66 nm. For
c0 =
0.1 nm
1 the minimal
energy of 2.68
32 kT occurs at r = 1.54 nm.
Stress-free stalk
Now we shall no longer make the assumption that the stalk is
circular in shape but instead its shape will be calculated. Therefore in Fig. 1 A parameter r should be disregarded and
the stalk is considered to be a figure of revolution of a certain
arbitrary curve. In this curve a is its shortest distance
from the axis of revolution, b is the point where the stalk
smoothly connects with the rest of the planar membrane. For simplicity,
the initial membranes are considered planar. 2H is the
distance between neutral surfaces of fusing layers. The contour is
supposed to be smooth, and no sharp points are allowed.
The principal curvatures of the stalk (Deuling and Helfrich, 1977
;
Volkov et al., 1998
; Markin et al., 1999
) are given by equations
|
(5)
|
To find the stress-free stalk we impose the condition that the
total curvature of the stalk is constant and equal to
cstalk:
|
(6)
|
If cstalk = c0, the
stalk is stress free.
This approach was used previously for the analysis of myelin shapes
(Deuling and Helfrich, 1977
) and beading of nerve fibers under lateral
tension (Markin et al., 1999
). The contour of the stalk neutral surface
can be presented (Volkov et al., 1998
; Markin et al., 1999
) as
|
(7)
|
For the contour in Fig. 2, one can
find from Eq. 5 that
|
(8)
|
Then the final equation for the contour takes the form
|
(9)
|
Parameter b of the stalk can be found from the
condition dz/dx = 0; then
|
(10)
|
The last equation shows that the ratio b/a depends on a
single dimensionless parameter acstalk. The same
is true for the shape of the stalk z = z(x) given by
the following equation:
|
(11)
|
As one can see from here, the shape of the stalk is indeed
determined by a single parameter acstalk because
the upper limit of this integral b/a is also a function of
the same parameter according to Eq. 10. In Fig. 2 A we
presented the contour of the stalk neutral surface with parameters
acstalk =
0.1. One can see that the
contour of the stalk is not a circular arc and that its branches at the
end become horizontal. The important point is that if
cstalk = c0, then this
stalk is completely stress free because its total curvature at every
point is equal to the spontaneous curvature c0.
Fig. 2 B gives a three-dimensional view of that stalk (of
its neutral surface).

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FIGURE 2
Stress-free stalk. (A) Two-dimensional
contours for three different spontaneous curvatures shown in the graph.
(B) Three-dimensional rendition of the stalk with
c0 = 0.1 nm 1.
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|
The height of the stalk L = 2H is found from the
integral (Eq. 11) with x = b. In the absence of an
analytical solution for the stress free stalk (Eq. 11) it is useful to
have a good approximation for it. From the analysis of series expansion
of (Eq. 11) at points x = a and x = b
one can find a piece-wise approximating function for L:
|
(12a)
|
and
|
(12b)
|
Notice that the dimensionless normalized distance L/a
depends on a single parameter, acstalk, only.
This function is presented in Fig. 3
A together with a numerical solution (Eq. 11). Two lines are
indistinguishable at this resolution demonstrating that function (Eq.
12) closely approximates the distance between fusing membranes. Practically, one cannot expect that acstalk
would reach a high negative value. Therefore we need only the values
between
1 and
0.001, given by Eq. 12b. Hence the distance between
membranes (neutral surfaces) is given by
|
(13)
|
Notice, that this relationship does not depend on
membrane stiffness
.

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FIGURE 3
Parameters of the stress-free stalk. (A)
Normalized height of the stalk L/a as the function of
acstalk. (B) Height of the stalk
L as a function of the neck radius a for
different values of spontaneous curvature cstalk
shown at the curves in nm 1.
|
|
Equation 12 and the resulting plot in Fig. 3 A have
universal character applicable at any (negative) spontaneous curvature. However, for practical purposes a dimensional Eq. 13, illustrated in
Fig. 3 B for a few selected values of
c0, is more convenient.
Stalk energy
Now let us determine the energy of the stalk. Because the
curvature of the stalk is constant and equal to
cstalk, its bending energy is
1/2
(cstalk
c0)2 A, in which A is the area
of the stalk. If cstalk = c0, bending energy is zero. We have to subtract from
here the initial energy of the membrane in the planar state if
spontaneous curvature is not zero. In the planar state fusing layers
have elastic energy equal to
1/2
c02 A.
Therefore the energy of the stalk is
|
(14)
|
Notice that the energy of the stress free stalk is
1/2
c02A and it is
negative. To complete this calculation we have to find stalk area
A. If the infinitesimal length of the contour in Fig. 1
A is dl = dx/cos
, the differential of
the area can be found as
|
(15)
|
And hence
|
(16)
|
Now the total energy of the stalk can be presented as
|
(17)
|
The dependence of the stalk energy on its radius a is
presented in Fig. 4 for different values
of spontaneous curvature c0. As one can conclude
from here, the stalk has negative energy, it tends to expand and to
push away fusing membranes. For comparison with previous results we
present in Table 1 the energy of the initial monolayer stalk (astalk = 1 nm)
both for the old model and the new one in units of kT. One can see a
huge difference between the two models.

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FIGURE 4
Bending energy of the stress-free stalk with different
c0 shown at the curves in nm 1 as a
function of its radius a (below abscissa). Above abscissa
there are two curves with zero or small positive spontaneous curvature;
these stalks are not stress free, however, their bending energy is very
small.
|
|
Hemifusion
Let us consider the initial hemifusion structure presented
in Fig. 1 B. At some point P the trans
monolayer peels off of the cis monolayer. Let this point
have coordinate xp and angle
=
p. Designate the corresponding points at the neutral
surfaces of cis and trans monolayers
x1 and x2. The surface
between the two monolayers will be considered a reference surface and
its curvature will be designated cb. The whole
structure can be divided into three parts: the "wings" of the
hemi-fused bilayers beyond the point x = x1, the "neck" of the stalk in the range
x < x1, and two dimples formed by
trans monolayers in the range x < x2. The monolayers of these three parts are smoothly
connected to each other. The total energy of hemifusion
Wh consists of the bending energy of the neck
Wn, of the wings Ww, of
the dimples Wd, and hydrophobic energy of two voids Wv. We shall calculate each of these components.
First, let us find coordinate x1. If the
stalk has curvature cs and the neck radius
a, then from Eqs. 5 and 8 one can find that
|
(19)
|
and then
and
|
(20)
|
The energy of the stalk neck Wneck
can be readily found from Eq. 17 if the integral is taken from 1 to
x1/a.
Calculation of the energy of the wings Ww
is more complicated. We select the interface between two monolayers as
a reference surface, and coordinates of monolayer neutral surfaces will
be related to this reference surface. As in the previous section, we
assume that the reference surface has constant total curvature. This
assumption will be discussed later. The principal curvatures cm and cp of the
reference surface are defined the same way as for a monolayer stalk by
Eq. 5. That means that cm < 0 and
cp > 0. Designate
the distance from
the hydrophilic surface of a monolayer to its neutral surface. Then the
principal curvatures of the cis monolayer are given by the
equations
|
(21)
|
The curvatures of the trans monolayer have the
opposite sign and can be presented as
and
|
(22)
|
Notice that these definitions are consistent for both
monolayers. We "look" at a monolayer from the aqueous phase: if the monolayer in a given principal plane is convex, then this curvature is
positive and vice versa. The geometry of the wings of the hemi-fused bilayer is determined by a set of three parameters:
xp,
p, and cb. One can find that the principal curvatures
of the reference surface of the hemi-fused bilayer are given by
and
|
(23)
|
Instead of Eq. 10 the length of the wings is given by
|
(24)
|
and the area differential is
|
(25)
|
The bending energy density of the bilayer wings, referred to its
reference surface, can be presented as
|
(26)
|
in which c
is the
spontaneous curvature of the cis monolayer and
c
is the same for the trans monolayer.
The total free energy of the bilayer wings is given by the integral
over the area of the reference surface from radius
xp to bw:
|
(27)
|
To estimate the dimple energy we assume that it has a
spherical shape. Its radius is rd = x2/sin
p, and hence the bending energy
of two dimples is
|
(28)
|
Total bending energy of the hemi-fused bilayers is
|
(29)
|
For the sake of comparison with previous numerical results we
assume that
= h/2 = 1 nm,
= 10 kT,
and
p =
/6. Suppose that monolayers have no
spontaneous curvature. Then the stress free stalk neck does not
contribute any energy to Eq. 26. Bilayer wings contribute
Ww = 2.8 kT and dimples have
Wd = 33.7 kT. Therefore in total bending
energy of Whb (36.5 kT) the main contribution comes from the dimples and constitutes approximately 92% of the total.
The presence of spontaneous curvature in monolayers helps to decrease
the bending energy of hemifusion. For example, if
c0 of both monolayers is
0.1 nm
1
and
p = 30°, then Wn =
1.1 kT, Ww =
2.7 kT,
Wd = 28.4 kT, and the total is only
Whb = 24.6 kT.
The result strongly depends on where the monolayer peel-off occurs,
i.e. what is the value of the peel-off angle. If it happens a little
farther from the axis of the stalk then the bending energy drastically
decreases. For example, if
p = 15° and there is
no spontaneous curvature then Ww = 0.1 kT,
Wc = 8.4 kT, and the total is only
Whb = 8.5 kT.
Finally, if the peel-off point occurs at
p = 15°
and spontaneous curvature is c0 =
0.1
nm
1, then Wn =
2.5 kT,
Ww =
1.6 kT,
Wc = 1.4 kT, and the total becomes negative
Whb =
2.7 kT.
Therefore, the bending energy of the hemifused bilayers can be
very low and even negative if the monolayers have rather pronounced spontaneous curvature. Fig. 5
A presents the bending energy of hemifusion as a function of
peel-off angle for two types of bilayer: with no spontaneous curvature
of monolayers and with c0 =
0.1 nm
1. As one can see, in the absence of spontaneous
curvature the bending energy would be zero if
p = 0°. This obviously means that the trans monolayer would
prefer to remain planar. In the presence of spontaneous curvature
c0 =
0.1 nm
1 the bending
energy would reach a minimum at
p = 5° and it
would be negative at this configuration and equal to
8 kT.

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FIGURE 5
Free energy of the hemifusion as a function of peel-off
angle p for two types of bilayer: with no spontaneous
curvature and with c0 = 0.1
nm 1. (A) Bending energy only. (B)
Total energy of hemifusion, eff = 1.9 mN/m = 0.48 kBT/nm2.
|
|
The actual value of the peel off angle is determined by the minimum of
the total free energy of the system including the bending energy and
the energy of interstices at the stalk axis. It will be considered in
the next section.
Hydrophobic voids
Siegel was the first to pay attention to the fact that at
the ends of a monolayer stalk there should be void interstices (Markin and Hudspeth, 1993
; Siegel, 1993
) because three lipid monolayers meeting here cannot fit together without gaps. The shape of the interstices at the initial stage of hemifusion is presented in Fig.
6. The voids carry two additional
contributions to the total energy of the system associated with their
volume, V, and area, A:
|
(30)
|
Assuming that the void is nothing but vacuum, one can estimate the
first term as
|
(31)
|
in which Patm is atmospheric pressure.
However, 1 atm is equivalent to 0.025 kT/nm3. Therefore
even if the void volume amounts to a few dozens of nm3 (and
this is all we deal with in the stalk model),
Wvoid,V barely reaches 1 kT and hence can be
safely neglected.
The hydrophobic energy of the void was initially estimated by Siegel in
1993 (Siegel, 1993
) and subsequently corrected in 1999 (Siegel, 1999
).
The estimate was based on the assumption that the hydrophobic
interstice surface is equivalent to the surface of long chain alkanes
with vacuum, which is known to be in the range 20 to 27 mN/m. However,
using these numbers to find the energy of interstices in the
HII phase one would come up with energy that is an order of
magnitude higher than what is known for the HII phase
(Siegel, 1993
). The reason is that much of the "surface area" of
the interstice lies at the rim of the interstice, where two
lipid/vacuum interfaces would be less than 0.1 nm apart. In this case
one cannot use the surface tension of the free surface lest the energy
be strongly overestimated. There are two solutions to this dilemma. One
might try to take into consideration the existence of the other
hydrophobic surface in close proximity and calculate the energy of two
surfaces as the function of the distance between them. However, this
path involves rather poorly known functions and in the complex geometry
of interstices these calculations could give a very approximate result.
One can of course try to approximate the interstice geometry with a
simple geometrical shape, like a cylinder (Kuzmin et al., 2001
), but this approach completely neglects the interstices at the initial stage
of hemifusion (Fig. 6).
A different approach was proposed in Siegel (1999)
that was based on
surface area scaling. Siegel suggested using an "effective surface
tension" and found it to be
eff = 1.9 mN/m = 0.48 kBT/nm2. This
approach seems quite reasonable and convenient in practical implementation. We shall use it below.
Based on the previous equations for the shape of trans and
cis monolayers we calculated the area of voids
Avoid and found their hydrophobic energy
Wvoid =
eff
Avoid. Total energy of the hemifusion is equal
to
|
(32)
|
and it is a function of the stalk radius as
and peel-off angle
p. Actual shape of the hemifusion
structure is determined by interplay between bending energy and
hydrophobic energy. At a given as angle
p is determined by the minimum of the total energy.
Fig. 5 B presents the total energy of hemifusion as a
function of peel-off angle for two cases: c0 = 0 and c0 =
0.1 nm
1.
Both curves display a minimum. However, positions of these two minima
are quite different. The bilayer with no spontaneous curvature has a
minimum of 50 kT at
p = 26.4°, whereas in the
second case there is much lower minimum of 28.8 kT at
p = 22.2°.
When the stalk enlarges, the energy of hemifusion as well as the
peel-off angle change. Fig. 7 presents
the free energy of hemifusion as a function of stalk radius
as and peel-off angle
p for
different spontaneous curvatures of monolayers. Effective hydrophobic
surface tension was assumed equal to
eff = 0.48 kBT/nm2. The lines
connect the points with equal free energy of the system, and following
the tradition of using Greek names for such types of curves (e.g.,
isochors and isobars), we shall call them isergons. (The term was
proposed by A. J. Hudspeth.)

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FIGURE 7
Isergones, lines of equal free energy at the plane with
coordinates stalk radius as-peel-off angle
p. Effective hydrophobic surface tension
eff = 0.48 kBT/nm2. (A)
c0 = 0. (B)
c0 = 0.348 nm 1.
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|
As one can see here the energy of the hemifusion structure quickly
increases with its radius unless spontaneous curvature is very high as
in Fig. 7 B where we took dioleoylphosphatidylethanolamine (DOPE) spontaneous curvature c0 =
0.348
nm
1. This is somewhat puzzling because this would
virtually preclude the initial hemifusion structure from evolving into
transmembrane contact as in Fig. 1 C and would be even less
favorable for an extended trilaminar structure.
However, there is a possibility that the actual void hydrophobic
energy can be drastically decreased. The void energy can be very large
for pure bilayers of a single lipid component, but it will
significantly decrease for bilayers formed from lipid mixtures or
containing small amount of impurities, which may fill the voids. Siegel
(1999)
noted that in biological membranes, the voids forming around the
stalk might have much lower energy because they could be filled up with
some impurities always present in the membrane. Even minute fractions
of apolar lipid like triglycerides and dolichol could lower the energy
of TMCs by up to 50 to 80 kT. This might practically eliminate the
hydrophobic energy of interstices, reducing the total energy of
intermediate structures to the bending energy only.
But is there enough oil in the membrane to fill the hemifusion
interstices? The equilibrium solubility of long chain alkanes or other
long chain apolar oils in a bilayer is typically a few volume percent.
For our estimate let us take the lower limit of 1% only. Then for the
initial hemifusion structure with as = 1 nm, the necessary amount of oil would be found in two fusion bilayers inside the circle with radius of 3.13 nm. This hardly exceeds the bent
portion of the bilayers involved in hemifusion. Therefore, enough oil
can be squeezed just from the stalk proper to fill up the interstices.
This result holds for a moderate enlargement of the hemifusion so that
the hydrophobic void energy can be drastically decreased if not
eliminated completely. To illustrate this we repeated the previous
calculation for effective surface tension reduced to 1/5 of its
tentative value and c0 =
0.1
nm
1. Then the initial hemifusion structure has less than
5 kT of energy; when the radius as increases
from 1 to 2 nm, the energy grows only to 10 kT. In this case all the
evolutions leading to stalk enlargement, to transmembrane contact, and
to complete fusion become eminently possible.
Deformation of tilt
Another way to eliminate the voids in the hemifusion structure is
to shift lipid molecules to the void space. In principle, lipid
molecules can displace in the direction normal to the monolayer, and by
doing so they could fill up the voids of hemifusion (Fig. 8). Of course this would happen at a
cost. Normal displacement of lipid molecules represents a different
kind of membrane deformation
deformation of tilt. During the last
decade, the deformation of tilt attracted the attention of many
researchers (Mackintosh and Lubensky, 1991
; May, 2000
; Hamm and Kozlov,
2000
and references therein). Kuzmin et al. (2001)
suggested that this
deformation can occur during membrane fusion and hence should be taken
into consideration. Let us estimate the energy cost that could be
expected for this deformation and if it will be compensated by the
release of hydrophobic energy after void collapse.

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FIGURE 8
Tilt deformation in HII phase.
(A) Cross-section of the void space between three lipid
cylinders. (B) Collapse of the void space.
|
|
As a specific example let us consider the interstices in the
HII phase (Fig. 8 A) formed by DOPE (Siegel,
1993
; Fuller and Rand, 2001
). Assuming that the lipidic phase has the
shape of circular cylinders Siegel called the hydrophobic voids between them trilaterally symmetric voids. In cross section (Fig. 8
A) these voids have the shape of curvilinear triangles.
Siegel estimated the energy required to produce a unit length of such
void configuration equal to 41.6 pN or 5 kT/nm.
Is it possible that the void space between three HII
cylinders would collapse, i.e., that the three monolayers in Fig. 8
A deform in such a way that they would fill up this void
space? To answer this question one has to compare the energy of the
void WTV including the hydrophobic energy of the
tails and bending energy of initial monolayers with deformation energy
of the collapsed void Wcollapse. The system will
acquire configurations with lower energy.
Deformation of tilt can be described by parameter of tilt that in
a simple case can be visualized as an angle
between the axis of
lipid molecule and the normal to the monolayer. Departure of this angle
from 0° exposes a portion of hydrophobic surfaces of lipid molecules
and hence increases the energy of the monolayer. To take this into
consideration one has to add to the bending energy (Eq. 1) an
additional term with tilt energy
1/2

2. In line with Eq. 1, one
can also include into this expression a certain spontaneous value of
tilt
0, changing it to
1/2
(
0)2. However, here we limit ourselves to the
simplest form of the tilt energy.
Collapse of the void in Fig. 8 means that the upper monolayer CB shifts
to position AB and becomes planar. The other monolayers lining the void
are transformed in a similar way. The orientation of lipid
molecules
tilt angle
(x)
in the new, planar
configuration of the monolayer between A and B changes from
/6 to 0:
|
(33)
|
Let us find the deformation energy of planar monolayers in the
collapsed configuration. At first glance it might seem counterintuitive but the planar monolayer AB has not only tilting but also bending energy. This statement deserves some additional explanation although it
was already presented in Hamm and Kozlov (2000)
and Kuzmin et al.
(2001)
.
What is the nature of the bending deformation? It is actually the
change of the shape of lipid molecules. Bending results in different
changes of the cross section (not simply the size) of heads and tails
of lipid molecules. The curvature of the initial monolayer CB is
negative so that lipid heads are compressed and tails are expanded.
Axes of lipid molecules have different orientation in space, although
they remain normal to the monolayer surface: there is no tilt. Now let
as perform a gedanken experiment: transform monolayer CB into monolayer
AB in such a way that all orientations of lipid molecules are
preserved. In this transformation the lipid molecules slide along each
other (along their axis) without changing their molecular shapes.
Therefore, the bending energy determined by the shape of the molecules
is preserved. Now from comparison of molecular orientation of the
monolayers CB and AB it is not difficult to figure out that in the new,
planar configuration AB the role of curvature c is played by
the derivative d
/dx. Transition from CB to AC involves a
certain work due to exposure of lateral surfaces of lipid molecules to
aqueous surrounding, which is proportional to
2. The
density of deformation energy in the collapsed monolayers can be
presented as
|
(34)
|
Here, as before,
is the bending modulus, whereas

is the tilt modulus.
The total deformation energy of the collapsed void per unit length is
|
(35)
|
where coefficient 6 accounts for six equivalent parts of the total
perimeter of the void cross section.
Of course orientation of lipid molecules in the planar monolayer AB
will not remain the same as in the original monolayer CB. It will relax
to the new positions
(x) to minimize the energy of the
total monolayer. According to calculus of variations, the function
(x) that minimizes the integral (Eq. 35) is determined by
the Euler equation
|
(36)
|
As one can see from the dimension analysis, this equation defines
a characteristic constant of length,
|
(37)
|
that gives the range of the monolayer where tilting and bending of
lipid molecules occur. Beyond this range the planar monolayer is free
of both tilting and bending. Notice that spontaneous curvature c0 that was present in the deformation energy
Eq. (34) disappeared from the Euler Eq. 36. Boundary conditions for
this differential equation are given by Eq. 33.
Solution of the Euler Eq. 36 is
|
(38)
|
in which l is the distance between points A and B and
deformation energy is
|
(39)
|
To estimate the collapse energy Wcollapse
one needs to know the value of the tilt modulus 
.
Unfortunately there are no direct experimental measurements of this
material constant. In the absence of direct measurements Hamm and
Kozlov (2000)
estimated it at 40 mN/m, whereas Kuzmin et al. (2001)
came up with 33 mN/m. Although these estimates were based on different
models, the results are rather close and can be summarized as 9 kT/nm2. That gives the characteristic length
= 1.05 nm.
The other parameters can be taken from Fuller and Rand (2001)
:
Rh = 4 nm, RN = 2.9 nm, RW = 2.18 nm,
= 0.73 nm,
and c0 =
1/RN. Then the
energy of collapsed void is 4.1 kT/nm. This result is not very
different from the open void energy of 5 kT/nm found by Siegel (1999)
;
therefore, these two configurations are energetically virtually equivalent.
Equation 39 can be used for estimation of the energy of the trilaminar
structure that could appear after further expansion of the stalk. Using
the fact that the open void has approximately the same energy as the
collapsed one, we shall use this equation for our estimation. Notice
that the last term in Eq. 39 represents the energy of the monolayer in
the initial, planar state. If we refer the energy of the trilaminar
structure to the planar state, then this amount should be subtracted
from the final energy. Besides, we assume that the length l
is large in the characteristic scale of the system, i.e., it
considerably exceeds 1 nm. Then the energy of the unit of length of the
trilaminar contact is given by
|
(40)
|
The physical meaning of this quantity is a linear tension, which
is why the designation f is used here.
To estimate the linear tension of the trilaminar contact, consider
bilayers without spontaneous curvature. Then
ftri = 7.8 kT/nm. The presence of negative
spontaneous curvature noticeably decreases this tension; for example,
if c0 =
0.1 nm
1 then
ftri = 4.7 kT/nm. This linear tension can
even become zero, if c0=
(
A/2 )
= 
A/2
. Numerically it gives
c0 =
0.25 nm
1, which is not
very far from the spontaneous curvature of DOPE that readily forms the
HII phase.
In the absence of spontaneous curvature there is only one term,
1/2 

, left in the braces of Eq. 40. This term represents both bending and
tilting energy, which give equal contributions to the total trilaminar
energy. This can be demonstrated in the following way. Angle
exponentially decreases with coordinate:
(x)=
A exp (
x/
) .
Therefore, the tilting energy changes as
wtilt (x)=(


/2) exp (
2x/
) .
After integration it becomes
1/4 



= 1/4
. This is exactly
one-half of the total energy of thetrilaminar structure. The other
one-half is contributed by the bending energy.
Complete fusion-fusion pore
The next step after formation of the hemifusion structure is
rupture of the trans monolayers and completion of the fusion process (Fig. 1 D). At this moment a fusion pore is formed,
and the fusion process is completed. Here we analyze the energetic cost
of the fusion pore and of its consequent enlargement. In the previous
sections we have considered the free energy associated with bilayer
wings included in the hemifusion structure. It was found that its
energy contribution was insignificant. However, this does not mean that
completely fused bilayers have negligible energy. The reason is that
the bending energy is concentrated at the neck of the fusion pore.
In the literature there are different approaches to the calculation of
this energy. In the simplest one (Markin et al., 1984
; Chizmadzhev et
al., 1995
) the bilayer is visualized as a single layer with bending
rigidity equal to the sum of the bending rigidity of the monolayers.
Originally this model was called a bilayer stalk and it resulted in the
same equations that were derived from a monolayer stalk. In the old
model the minimal energy of such a bilayer stalk with bending rigidity
10
19 J was found to be 90 kT (Chizmadzhev et al., 1995
).
However, this is a gross underestimation because two monolayers are
bent quite independently, and their elastic energy should be calculated separately. If this were done, then this value would increase to 150 kT.
So the old model predicts very high elastic energy for a fusion pore
due to the assumption of a circular shape for its neutral surface. In
the present approach the shape of the neutral surface is calculated
with constant total curvature. As we have seen above, for a single
monolayer this results in the stress-free stalk. However, this result
cannot be extended to a bilayer because its monolayers cannot be made
stress free simultaneously. However, their energy can be made much
lower than in the old model.
We calculate the bending energy of the bilayer using the equations
derived in the Hemifusion section. We select the interface between two
monolayers as a reference surface (Fig. 1 D). Its principal
curvatures cm and cp are
defined the same way as for a monolayer stalk by Eq. 5. The principal
curvatures of the cis and trans monolayer are
defined at their respective neutral surfaces and are presented by Eqs.
21 and 22. As we mentioned before these definitions are consistent for
both monolayers: if the monolayer in a given principal plane is convex,
then the given curvature is positive and vice versa. However, two
monolayers are bent in the opposite directions. For an example, let us
consider parallel curvatures at the equatorial plane. According to our
convention, the bilayer parallel curvature cp
here is positive, and the radius of the bilayer parallel curvature
obviously exceeds the monolayer thickness:
Rp = 1/cp > h. From Eqs. 21 and 22 one finds that
c
> 0 and
c
< 0, just confirming that two
monolayers are bent in the opposite directions and determining the sign
of their curvature.
Now let us see how the curvature of both monolayers varies along the
bilayer. We shall look for the solution where the reference surface of
the bilayer has a constant total curvature
cm + cp = cb and the radius of its "waist" is
ab. Then the principle curvatures of the bilayer
are
and
|
(41)
|
These equations are similar to the stalk equations, but here it is
explicitly stressed that the radius of the bilayer waist is
ab. As one can see, the sum of these two
curvatures (total curvature, ctot = cp + cm) equals
cb, but for separate monolayers this sum is not
a constant but rather varies along the bilayer. Fig.
9 illustrates how the total curvature of
trans and cis monolayers varies with x
for different values cb equal correspondingly to
0.1,
0.01, and
0.001 nm
1. A horizontal line in each
panel presents the total curvature of the bilayer reference surface.